By Clay C. Ross

This introductory differential equations textbook provides a handy approach for professors to combine symbolic computing into the examine of differential equations and linear algebra. Mathematica presents the required computational energy and is hired from the very starting of the textual content. each one new inspiration is interactively constructed utilizing it.

After first studying concerning the basics of differential equations and linear algebra, the scholar is straight away given a chance to envision each one new inspiration utilizing Mathematica. All principles are explored using Mathematica, and even though the pc eases the computational burden, the coed is inspired to consider what the computations show, how they're in line with the maths, what any conclusions suggest, and the way they are applied.

This new version updates the textual content to Mathematica 5.0 and gives a extra huge therapy of linear algebra. it's been completely revised and corrected all through.

Dr. Clay C. Ross taught arithmetic on the collage point from 1967 via his retirement in may possibly of 2003. He maintains to pursue his pursuits in arithmetic, commute and nature images, nonetheless performs within the collage orchestra, and serves as organist at his church. these actions and masses analyzing preserve him productively occupied.

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**Additional resources for Differential Equations: An Introduction with Mathematica®**

**Example text**

Using properties of sums, multiples and composition of linear operators, explain why each of these operators is linear: a) L 1(y) = y' + 3y; b) L2 (y) = Sy' + 2y; c) L 3 (y) = y" + 4y' + y; d) L4 (y) = y"- Sy; e) L 5 (y) = yrs)- 7y< 4 ) + 3y"- 2y. 3. Show by induction that derivatives of any order are linear. 4. Show by induction that any finite sum of linear functions is linear. PART II. Perform the following operations on the given pairs A, B of matrices. AB, BA, A + B, B - A. Do this manually and by Mathematica.

The composition of two linear functions is linear. In other words, ifF is linear; G is linear; and the domain ofF contains the range of G, then the function L defined for each x in the domain ofG by L(x) = F(G(x)) is linear. Proof If u and v are in the domain of G and cis a number, then L(u + v) = F(G(u + v)) = F(G(u) + G(v)) = F(G(u)) + F(G(v)) = L(u) + L(v), and L(c u) = F(G(c u)) + F(c G(u)) = c F(G(u)) = c L(u). D An immediate consequence of the fact that the composition of linear functions is linear is that the second derivative function is linear.

We are especially interested in sets that are a basis for the spaces in which we have interest, because the members of a basis are genuinely and essentially different from one another. They are exactly enough to describe the set of interest: fewer would not do the job; more would be redundant. When we solve homogeneous linear differential equations, we will always seek a basis for the set of solutions. When we looked at kernels before, the "complete description of the kernel" that we sought can be given in terms of a basis.