By Benjamin Crowell

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**Sample text**

These two quantities can’t both equal F d. Most of the energy transmitted through the cable goes into frictional heating of the plow and the dirt. The work done by the plow on the dirt is less than the work done by the tractor on the plow, by an amount equal to the heat absorbed by the plow. It turns out that the equation W = F d gives the work done by the tractor, not the work done by the plow. How are you supposed to know when the equation will work and when it won’t? 6. Until then, we will restrict ourselves to examples in which W = F d gives the right answer; essentially the reason the ambiguities come up is that when one surface is slipping past another, d may be hard to define, because the two surfaces move different distances.

But if the curve had not been so geometrically simple, it might not have been possible to find a simple equation for the work done, or an equation might have been derivable only using calculus. 4 gives an important example of such an application of calculus. Energy production in the sun example 4 The sun produces energy through nuclear reactions in which nuclei collide and stick together. The figure depicts one such reaction, in which a single proton (hydrogen nucleus) collides with a carbon nucleus, consisting of six protons and six neutrons.

Since these are topics for books 4, 5, and 6 of this series, we will have to be content with half an answer at this point. Essentially we may think of light energy as a form of kinetic energy, but one for which kinetic energy is not given by (1/2)mv 2 but rather by some other equation. ) Discussion Question A Referring back to the pictures at the beginning of the chapter, how do all these forms of energy fit into the shortened list of categories given above? f / This figure looks similar to the previous ones, but the scale is a million times smaller.